Base | Representation |
---|---|
bin | 11000010010110110… |
… | …10000111110010001 |
3 | 1020122222210022001122 |
4 | 30021123100332101 |
5 | 203203004403431 |
6 | 5554125412025 |
7 | 641135022023 |
oct | 141133207621 |
9 | 36588708048 |
10 | 13043044241 |
11 | 5593505207 |
12 | 264010a015 |
13 | 12cb293076 |
14 | 8ba372013 |
15 | 515105a7b |
hex | 3096d0f91 |
13043044241 has 2 divisors, whose sum is σ = 13043044242. Its totient is φ = 13043044240.
The previous prime is 13043044229. The next prime is 13043044291. The reversal of 13043044241 is 14244034031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7641382225 + 5401662016 = 87415^2 + 73496^2 .
It is a cyclic number.
It is not a de Polignac number, because 13043044241 - 218 = 13042782097 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13043044241.
It is not a weakly prime, because it can be changed into another prime (13043044291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521522120 + 6521522121.
It is an arithmetic number, because the mean of its divisors is an integer number (6521522121).
Almost surely, 213043044241 is an apocalyptic number.
It is an amenable number.
13043044241 is a deficient number, since it is larger than the sum of its proper divisors (1).
13043044241 is an equidigital number, since it uses as much as digits as its factorization.
13043044241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 26.
Adding to 13043044241 its reverse (14244034031), we get a palindrome (27287078272).
The spelling of 13043044241 in words is "thirteen billion, forty-three million, forty-four thousand, two hundred forty-one".
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