Base | Representation |
---|---|
bin | 1011110111001101011011… |
… | …0010011000011110001010 |
3 | 1201011220120202101000112021 |
4 | 2331303112302120132022 |
5 | 3202144304301223224 |
6 | 43423532322435054 |
7 | 2514222530535355 |
oct | 275632662303612 |
9 | 51156522330467 |
10 | 13043124242314 |
11 | 4179615668281 |
12 | 1567a17b02a8a |
13 | 737c660a306a |
14 | 33140d4db29c |
15 | 1794355a51e4 |
hex | bdcd6c9878a |
13043124242314 has 4 divisors (see below), whose sum is σ = 19564686363474. Its totient is φ = 6521562121156.
The previous prime is 13043124242311. The next prime is 13043124242329. The reversal of 13043124242314 is 41324242134031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11107455856225 + 1935668386089 = 3332785^2 + 1391283^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 13043124242314.
It is not an unprimeable number, because it can be changed into a prime (13043124242311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3260781060577 + ... + 3260781060580.
Almost surely, 213043124242314 is an apocalyptic number.
13043124242314 is a deficient number, since it is larger than the sum of its proper divisors (6521562121160).
13043124242314 is an equidigital number, since it uses as much as digits as its factorization.
13043124242314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6521562121159.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 13043124242314 its reverse (41324242134031), we get a palindrome (54367366376345).
The spelling of 13043124242314 in words is "thirteen trillion, forty-three billion, one hundred twenty-four million, two hundred forty-two thousand, three hundred fourteen".
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