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130431303412200 = 233252768315156209
BaseRepresentation
bin11101101010000001100111…
…100000011110100111101000
3122002211002222210110202112200
4131222001213200132213220
5114043441302133142300
61141223151422540200
736321231201213060
oct3552014740364750
9562732883422480
10130431303412200
113861767249151a
1212766563737660
1357a180831972b
14242cca19383a0
151012c3e232200
hex76a06781e9e8

130431303412200 has 288 divisors, whose sum is σ = 501340751870400. Its totient is φ = 29769217505280.

The previous prime is 130431303412187. The next prime is 130431303412253. The reversal of 130431303412200 is 2214303134031.

It is a happy number.

130431303412200 is a `hidden beast` number, since 1 + 3 + 0 + 4 + 313 + 0 + 341 + 2 + 2 + 0 + 0 = 666.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 1027696 + ... + 16183904.

It is an arithmetic number, because the mean of its divisors is an integer number (1740766499550).

Almost surely, 2130431303412200 is an apocalyptic number.

130431303412200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130431303412200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (250670375935200).

130431303412200 is an abundant number, since it is smaller than the sum of its proper divisors (370909448458200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130431303412200 is a wasteful number, since it uses less digits than its factorization.

130431303412200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15156921 (or 15156909 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 130431303412200 its reverse (2214303134031), we get a palindrome (132645606546231).

The spelling of 130431303412200 in words is "one hundred thirty trillion, four hundred thirty-one billion, three hundred three million, four hundred twelve thousand, two hundred".