Base | Representation |
---|---|
bin | 11101101010000011011001… |
… | …001110100110110110000011 |
3 | 122002211021220202120000122001 |
4 | 131222003121032212312003 |
5 | 114044004204100024143 |
6 | 1141224105020124431 |
7 | 36321326366230315 |
oct | 3552033116466603 |
9 | 562737822500561 |
10 | 130433211329923 |
11 | 38618461455327 |
12 | 127669b6696717 |
13 | 57a1a50693128 |
14 | 242d0030a37b5 |
15 | 1012d019a614d |
hex | 76a0d93a6d83 |
130433211329923 has 2 divisors, whose sum is σ = 130433211329924. Its totient is φ = 130433211329922.
The previous prime is 130433211329887. The next prime is 130433211330013. The reversal of 130433211329923 is 329923112334031.
It is a weak prime.
It is an emirp because it is prime and its reverse (329923112334031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130433211329923 - 229 = 130432674459011 is a prime.
It is not a weakly prime, because it can be changed into another prime (100433211329923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65216605664961 + 65216605664962.
It is an arithmetic number, because the mean of its divisors is an integer number (65216605664962).
Almost surely, 2130433211329923 is an apocalyptic number.
130433211329923 is a deficient number, since it is larger than the sum of its proper divisors (1).
130433211329923 is an equidigital number, since it uses as much as digits as its factorization.
130433211329923 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 629856, while the sum is 46.
The spelling of 130433211329923 in words is "one hundred thirty trillion, four hundred thirty-three billion, two hundred eleven million, three hundred twenty-nine thousand, nine hundred twenty-three".
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