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13043324221311 = 34347774740437
BaseRepresentation
bin1011110111001110001010…
…1101001111011101111111
31201011221002200200000010210
42331303202231033131333
53202200212000040221
643424004225003503
72514230506404456
oct275634255173577
951157080600123
1013043324221311
11417970853647a
121567a72a83593
13737c98650927
1433142bcb5b9d
15179447e08276
hexbdce2b4f77f

13043324221311 has 4 divisors (see below), whose sum is σ = 17391098961752. Its totient is φ = 8695549480872.

The previous prime is 13043324221283. The next prime is 13043324221321. The reversal of 13043324221311 is 11312242334031.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13043324221311 - 27 = 13043324221183 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13043324221321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2173887370216 + ... + 2173887370221.

It is an arithmetic number, because the mean of its divisors is an integer number (4347774740438).

Almost surely, 213043324221311 is an apocalyptic number.

13043324221311 is a deficient number, since it is larger than the sum of its proper divisors (4347774740441).

13043324221311 is an equidigital number, since it uses as much as digits as its factorization.

13043324221311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4347774740440.

The product of its (nonzero) digits is 10368, while the sum is 30.

Adding to 13043324221311 its reverse (11312242334031), we get a palindrome (24355566555342).

The spelling of 13043324221311 in words is "thirteen trillion, forty-three billion, three hundred twenty-four million, two hundred twenty-one thousand, three hundred eleven".

Divisors: 1 3 4347774740437 13043324221311