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130434444440212 = 22111789109173103903
BaseRepresentation
bin11101101010000100100010…
…101110100011001010010100
3122002211102002200212111221111
4131222010202232203022110
5114044014220234041322
61141224431230024404
736321402061420123
oct3552044256431224
9562742080774844
10130434444440212
1138618a34516340
121276709b648104
1357a1bb8cab1a3
14242d0bcb71aba
151012d74d82177
hex76a122ba3294

130434444440212 has 192 divisors, whose sum is σ = 270625365964800. Its totient is φ = 54351152824320.

The previous prime is 130434444440203. The next prime is 130434444440269. The reversal of 130434444440212 is 212044444434031.

It is a super-2 number, since 2×1304344444402122 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1255296253 + ... + 1255400155.

It is an arithmetic number, because the mean of its divisors is an integer number (1409507114400).

Almost surely, 2130434444440212 is an apocalyptic number.

It is an amenable number.

130434444440212 is an abundant number, since it is smaller than the sum of its proper divisors (140190921524588).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130434444440212 is a wasteful number, since it uses less digits than its factorization.

130434444440212 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 104306 (or 104304 counting only the distinct ones).

The product of its (nonzero) digits is 589824, while the sum is 40.

Adding to 130434444440212 its reverse (212044444434031), we get a palindrome (342478888874243).

The spelling of 130434444440212 in words is "one hundred thirty trillion, four hundred thirty-four billion, four hundred forty-four million, four hundred forty thousand, two hundred twelve".