Base | Representation |
---|---|
bin | 11000010010111001… |
… | …10011100001001001 |
3 | 1020200000112210202021 |
4 | 30021130303201021 |
5 | 203203110313011 |
6 | 5554142204441 |
7 | 641141322562 |
oct | 141134634111 |
9 | 36600483667 |
10 | 13043447881 |
11 | 55937604a2 |
12 | 2640283721 |
13 | 12cb3a49c9 |
14 | 8ba439169 |
15 | 515185471 |
hex | 309733849 |
13043447881 has 2 divisors, whose sum is σ = 13043447882. Its totient is φ = 13043447880.
The previous prime is 13043447869. The next prime is 13043447899. The reversal of 13043447881 is 18874434031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13042782025 + 665856 = 114205^2 + 816^2 .
It is an emirp because it is prime and its reverse (18874434031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13043447881 - 217 = 13043316809 is a prime.
It is a super-2 number, since 2×130434478812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13043447801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521723940 + 6521723941.
It is an arithmetic number, because the mean of its divisors is an integer number (6521723941).
Almost surely, 213043447881 is an apocalyptic number.
It is an amenable number.
13043447881 is a deficient number, since it is larger than the sum of its proper divisors (1).
13043447881 is an equidigital number, since it uses as much as digits as its factorization.
13043447881 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 258048, while the sum is 43.
The spelling of 13043447881 in words is "thirteen billion, forty-three million, four hundred forty-seven thousand, eight hundred eighty-one".
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