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13043447881 is a prime number
BaseRepresentation
bin11000010010111001…
…10011100001001001
31020200000112210202021
430021130303201021
5203203110313011
65554142204441
7641141322562
oct141134634111
936600483667
1013043447881
1155937604a2
122640283721
1312cb3a49c9
148ba439169
15515185471
hex309733849

13043447881 has 2 divisors, whose sum is σ = 13043447882. Its totient is φ = 13043447880.

The previous prime is 13043447869. The next prime is 13043447899. The reversal of 13043447881 is 18874434031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13042782025 + 665856 = 114205^2 + 816^2 .

It is an emirp because it is prime and its reverse (18874434031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13043447881 - 217 = 13043316809 is a prime.

It is a super-2 number, since 2×130434478812 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13043447801) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521723940 + 6521723941.

It is an arithmetic number, because the mean of its divisors is an integer number (6521723941).

Almost surely, 213043447881 is an apocalyptic number.

It is an amenable number.

13043447881 is a deficient number, since it is larger than the sum of its proper divisors (1).

13043447881 is an equidigital number, since it uses as much as digits as its factorization.

13043447881 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 258048, while the sum is 43.

The spelling of 13043447881 in words is "thirteen billion, forty-three million, four hundred forty-seven thousand, eight hundred eighty-one".