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130434714161 is a prime number
BaseRepresentation
bin111100101111010000…
…0111100101000110001
3110110200012221000100022
41321132200330220301
54114112241323121
6135530524333225
712265202530403
oct1713640745061
9413605830308
10130434714161
1150353aa5334
12213423a4215
13c3b8c7ba4b
146455108b73
1535d60d2aab
hex1e5e83ca31

130434714161 has 2 divisors, whose sum is σ = 130434714162. Its totient is φ = 130434714160.

The previous prime is 130434714133. The next prime is 130434714181. The reversal of 130434714161 is 161417434031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82272022561 + 48162691600 = 286831^2 + 219460^2 .

It is a cyclic number.

It is not a de Polignac number, because 130434714161 - 210 = 130434713137 is a prime.

It is not a weakly prime, because it can be changed into another prime (130434714181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65217357080 + 65217357081.

It is an arithmetic number, because the mean of its divisors is an integer number (65217357081).

Almost surely, 2130434714161 is an apocalyptic number.

It is an amenable number.

130434714161 is a deficient number, since it is larger than the sum of its proper divisors (1).

130434714161 is an equidigital number, since it uses as much as digits as its factorization.

130434714161 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 35.

The spelling of 130434714161 in words is "one hundred thirty billion, four hundred thirty-four million, seven hundred fourteen thousand, one hundred sixty-one".