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1304371494289 is a prime number
BaseRepresentation
bin10010111110110010100…
…110010111110110010001
311121200210220002101001001
4102332302212113312101
5132332323100304124
62435115303542001
7163144353523603
oct22766246276621
94550726071031
101304371494289
114631a9781596
1219096745a901
1396003989656
14471bbda3173
1523de2accb44
hex12fb2997d91

1304371494289 has 2 divisors, whose sum is σ = 1304371494290. Its totient is φ = 1304371494288.

The previous prime is 1304371494241. The next prime is 1304371494317. The reversal of 1304371494289 is 9824941734031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 723562890625 + 580808603664 = 850625^2 + 762108^2 .

It is a cyclic number.

It is not a de Polignac number, because 1304371494289 - 237 = 1166932540817 is a prime.

It is a super-2 number, since 2×13043714942892 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1304371494589) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652185747144 + 652185747145.

It is an arithmetic number, because the mean of its divisors is an integer number (652185747145).

Almost surely, 21304371494289 is an apocalyptic number.

It is an amenable number.

1304371494289 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304371494289 is an equidigital number, since it uses as much as digits as its factorization.

1304371494289 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5225472, while the sum is 55.

The spelling of 1304371494289 in words is "one trillion, three hundred four billion, three hundred seventy-one million, four hundred ninety-four thousand, two hundred eighty-nine".