130440000000000 has 572 divisors, whose sum is σ = 435146866088192. Its totient is φ = 34752000000000.

The previous prime is 130439999999917. The next prime is 130440000000017. The reversal of 130440000000000 is 44031.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 43 ways as a sum of consecutive naturals, for example, 119999999457 + ... + 120000000543.

Almost surely, 2^{130440000000000} is an apocalyptic number.

130440000000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130440000000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (217573433044096).

130440000000000 is an abundant number, since it is smaller than the sum of its proper divisors (304706866088192).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130440000000000 is an frugal number, since it uses more digits than its factorization.

130440000000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1164 (or 1097 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 12.

Adding to 130440000000000 its reverse (44031), we get a palindrome (130440000044031).

The spelling of 130440000000000 in words is "one hundred thirty trillion, four hundred forty billion", and thus it is an aban number.