Base | Representation |
---|---|
bin | 11101101010001001101101… |
… | …111000011111010100010010 |
3 | 122002211221102220012122211021 |
4 | 131222021231320133110102 |
5 | 114044112110034220102 |
6 | 1141231150415310054 |
7 | 36321656543451655 |
oct | 3552115570372422 |
9 | 562757386178737 |
10 | 130440000304402 |
11 | 38620325676338 |
12 | 1276819021b32a |
13 | 57a25930514a9 |
14 | 242d4889ab89c |
15 | 101309c9d9137 |
hex | 76a26de1f512 |
130440000304402 has 4 divisors (see below), whose sum is σ = 195660000456606. Its totient is φ = 65220000152200.
The previous prime is 130440000304399. The next prime is 130440000304417. The reversal of 130440000304402 is 204403000044031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 123750695700241 + 6689304604161 = 11124329^2 + 2586369^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32610000076099 + ... + 32610000076102.
Almost surely, 2130440000304402 is an apocalyptic number.
130440000304402 is a deficient number, since it is larger than the sum of its proper divisors (65220000152204).
130440000304402 is an equidigital number, since it uses as much as digits as its factorization.
130440000304402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65220000152203.
The product of its (nonzero) digits is 4608, while the sum is 25.
Adding to 130440000304402 its reverse (204403000044031), we get a palindrome (334843000348433).
The spelling of 130440000304402 in words is "one hundred thirty trillion, four hundred forty billion, three hundred four thousand, four hundred two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •