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130440000304402 = 265220000152201
BaseRepresentation
bin11101101010001001101101…
…111000011111010100010010
3122002211221102220012122211021
4131222021231320133110102
5114044112110034220102
61141231150415310054
736321656543451655
oct3552115570372422
9562757386178737
10130440000304402
1138620325676338
121276819021b32a
1357a25930514a9
14242d4889ab89c
15101309c9d9137
hex76a26de1f512

130440000304402 has 4 divisors (see below), whose sum is σ = 195660000456606. Its totient is φ = 65220000152200.

The previous prime is 130440000304399. The next prime is 130440000304417. The reversal of 130440000304402 is 204403000044031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 123750695700241 + 6689304604161 = 11124329^2 + 2586369^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32610000076099 + ... + 32610000076102.

Almost surely, 2130440000304402 is an apocalyptic number.

130440000304402 is a deficient number, since it is larger than the sum of its proper divisors (65220000152204).

130440000304402 is an equidigital number, since it uses as much as digits as its factorization.

130440000304402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65220000152203.

The product of its (nonzero) digits is 4608, while the sum is 25.

Adding to 130440000304402 its reverse (204403000044031), we get a palindrome (334843000348433).

The spelling of 130440000304402 in words is "one hundred thirty trillion, four hundred forty billion, three hundred four thousand, four hundred two".

Divisors: 1 2 65220000152201 130440000304402