130440000411241 has 8 divisors (see below), whose sum is σ = 137305398434400. Its totient is φ = 123574615872480.

The previous prime is 130440000411209. The next prime is 130440000411263. The reversal of 130440000411241 is 142114000044031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130440000411241 - 2⁵ = 130440000411209 is a prime.

It is not an unprimeable number, because it can be changed into a prime (130440000411841) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21004086 + ... + 26496256.

It is an arithmetic number, because the mean of its divisors is an integer number (17163174804300).

Almost surely, 2^{130440000411241} is an apocalyptic number.

It is an amenable number.

130440000411241 is a deficient number, since it is larger than the sum of its proper divisors (6865398023159).

130440000411241 is a wasteful number, since it uses less digits than its factorization.

130440000411241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6742199.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 130440000411241 its reverse (142114000044031), we get a palindrome (272554000455272).

The spelling of 130440000411241 in words is "one hundred thirty trillion, four hundred forty billion, four hundred eleven thousand, two hundred forty-one".