Base | Representation |
---|---|
bin | 11101101010001001101101… |
… | …111000111001011001111111 |
3 | 122002211221102220102002102002 |
4 | 131222021231320321121333 |
5 | 114044112110101130023 |
6 | 1141231150421452515 |
7 | 36321656544405344 |
oct | 3552115570713177 |
9 | 562757386362362 |
10 | 130440000411263 |
11 | 38620325739654 |
12 | 1276819027113b |
13 | 57a259308b01a |
14 | 242d4889d87cb |
15 | 101309ca0ab28 |
hex | 76a26de3967f |
130440000411263 has 2 divisors, whose sum is σ = 130440000411264. Its totient is φ = 130440000411262.
The previous prime is 130440000411209. The next prime is 130440000411311. The reversal of 130440000411263 is 362114000044031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130440000411263 - 224 = 130439983634047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130440000410263) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220000205631 + 65220000205632.
It is an arithmetic number, because the mean of its divisors is an integer number (65220000205632).
Almost surely, 2130440000411263 is an apocalyptic number.
130440000411263 is a deficient number, since it is larger than the sum of its proper divisors (1).
130440000411263 is an equidigital number, since it uses as much as digits as its factorization.
130440000411263 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 130440000411263 its reverse (362114000044031), we get a palindrome (492554000455294).
The spelling of 130440000411263 in words is "one hundred thirty trillion, four hundred forty billion, four hundred eleven thousand, two hundred sixty-three".
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