130440004333 has 4 divisors (see below), whose sum is σ = 130441183900. Its totient is φ = 130438824768.

The previous prime is 130440004319. The next prime is 130440004349. The reversal of 130440004333 is 333400044031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 24994977604 + 105445026729 = 158098^2 + 324723^2 .

It is a cyclic number.

It is not a de Polignac number, because 130440004333 - 2⁵ = 130440004301 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130440004298 and 130440004307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130440004363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 404508 + ... + 651541.

It is an arithmetic number, because the mean of its divisors is an integer number (32610295975).

Almost surely, 2^130440004333 is an apocalyptic number.

It is an amenable number.

130440004333 is a deficient number, since it is larger than the sum of its proper divisors (1179567).

130440004333 is a wasteful number, since it uses less digits than its factorization.

130440004333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1179566.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 130440004333 its reverse (333400044031), we get a palindrome (463840048364).

The spelling of 130440004333 in words is "one hundred thirty billion, four hundred forty million, four thousand, three hundred thirty-three".