13044001202320 has 160 divisors (see below), whose sum is σ = 33210538389504. Its totient is φ = 4725188390400.

The previous prime is 13044001202317. The next prime is 13044001202327. The reversal of 13044001202320 is 2320210044031.

It is a super-2 number, since 2×13044001202320² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a junction number, because it is equal to n+sod(n) for n = 13044001202291 and 13044001202300.

It is not an unprimeable number, because it can be changed into a prime (13044001202327) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1526859969 + ... + 1526868511.

Almost surely, 2^{13044001202320} is an apocalyptic number.

13044001202320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13044001202320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16605269194752).

13044001202320 is an abundant number, since it is smaller than the sum of its proper divisors (20166537187184).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13044001202320 is a wasteful number, since it uses less digits than its factorization.

13044001202320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14981 (or 14975 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 13044001202320 its reverse (2320210044031), we get a palindrome (15364211246351).

The spelling of 13044001202320 in words is "thirteen trillion, forty-four billion, one million, two hundred two thousand, three hundred twenty".