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130440022344403 = 4713720257807477
BaseRepresentation
bin11101101010001001101111…
…001100100100001011010011
3122002211221111102200102000121
4131222021233030210023103
5114044112131210010103
61141231152523531111
736321660232005352
oct3552115714441323
9562757442612017
10130440022344403
113862033705a312
1212768197689a97
1357a259779a305
14242d48b8a7999
15101309e8de6bd
hex76a26f3242d3

130440022344403 has 8 divisors (see below), whose sum is σ = 134187716734272. Its totient is φ = 126732843569856.

The previous prime is 130440022344397. The next prime is 130440022344419. The reversal of 130440022344403 is 304443220044031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130440022344403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130440022344503) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10128897300 + ... + 10128910177.

It is an arithmetic number, because the mean of its divisors is an integer number (16773464591784).

Almost surely, 2130440022344403 is an apocalyptic number.

130440022344403 is a deficient number, since it is larger than the sum of its proper divisors (3747694389869).

130440022344403 is a wasteful number, since it uses less digits than its factorization.

130440022344403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20257807661.

The product of its (nonzero) digits is 110592, while the sum is 34.

Adding to 130440022344403 its reverse (304443220044031), we get a palindrome (434883242388434).

The spelling of 130440022344403 in words is "one hundred thirty trillion, four hundred forty billion, twenty-two million, three hundred forty-four thousand, four hundred three".

Divisors: 1 47 137 6439 20257807477 952116951419 2775319624349 130440022344403