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13044004201023 = 36171278711481
BaseRepresentation
bin1011110111010000101100…
…1111001010001000111111
31201011222212002011112221120
42331310023033022020333
53202203110033413043
643424155515202023
72514253404213555
oct275641317121077
951158762145846
1013044004201023
114179a27351284
121568022746313
137380764a05a3
1433149431bbd5
15179487973983
hexbdd0b3ca23f

13044004201023 has 8 divisors (see below), whose sum is σ = 17677120447536. Its totient is φ = 8553445377600.

The previous prime is 13044004201021. The next prime is 13044004201027. The reversal of 13044004201023 is 32010240044031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13044004201023 - 21 = 13044004201021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13044004200984 and 13044004201002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044004201021) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35639355558 + ... + 35639355923.

It is an arithmetic number, because the mean of its divisors is an integer number (2209640055942).

Almost surely, 213044004201023 is an apocalyptic number.

13044004201023 is a deficient number, since it is larger than the sum of its proper divisors (4633116246513).

13044004201023 is an equidigital number, since it uses as much as digits as its factorization.

13044004201023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71278711545.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 13044004201023 its reverse (32010240044031), we get a palindrome (45054244245054).

The spelling of 13044004201023 in words is "thirteen trillion, forty-four billion, four million, two hundred one thousand, twenty-three".

Divisors: 1 3 61 183 71278711481 213836134443 4348001400341 13044004201023