Base | Representation |
---|---|
bin | 10010111110110100010… |
… | …111011110011000000111 |
3 | 11121200212221212200211200 |
4 | 102332310113132120013 |
5 | 132332403143041203 |
6 | 2435122243233543 |
7 | 163145163531066 |
oct | 22766427363007 |
9 | 4550787780750 |
10 | 1304401143303 |
11 | 463214492305 |
12 | 1909753788b3 |
13 | 96009b6a94b |
14 | 471c1cc01dd |
15 | 23de54d79a3 |
hex | 12fb45de607 |
1304401143303 has 24 divisors (see below), whose sum is σ = 1887644004480. Its totient is φ = 867981914640.
The previous prime is 1304401143257. The next prime is 1304401143343. The reversal of 1304401143303 is 3033411044031.
1304401143303 is a `hidden beast` number, since 1 + 304 + 4 + 0 + 11 + 43 + 303 = 666.
It is not a de Polignac number, because 1304401143303 - 216 = 1304401077767 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1304401143343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 24435600 + ... + 24488922.
It is an arithmetic number, because the mean of its divisors is an integer number (78651833520).
Almost surely, 21304401143303 is an apocalyptic number.
1304401143303 is a deficient number, since it is larger than the sum of its proper divisors (583242861177).
1304401143303 is a wasteful number, since it uses less digits than its factorization.
1304401143303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58339 (or 58336 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
Adding to 1304401143303 its reverse (3033411044031), we get a palindrome (4337812187334).
The spelling of 1304401143303 in words is "one trillion, three hundred four billion, four hundred one million, one hundred forty-three thousand, three hundred three".
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