13044012320021 has 4 divisors (see below), whose sum is σ = 13045101056844. Its totient is φ = 13042923583200.

The previous prime is 13044012319999. The next prime is 13044012320077. The reversal of 13044012320021 is 12002321044031.

13044012320021 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10515498903121 + 2528513416900 = 3242761^2 + 1590130^2 .

It is a cyclic number.

It is not a de Polignac number, because 13044012320021 - 2³⁴ = 13026832450837 is a prime.

It is a super-3 number, since 3×13044012320021³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044012320321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 544350440 + ... + 544374401.

It is an arithmetic number, because the mean of its divisors is an integer number (3261275264211).

Almost surely, 2^{13044012320021} is an apocalyptic number.

It is an amenable number.

13044012320021 is a deficient number, since it is larger than the sum of its proper divisors (1088736823).

13044012320021 is a wasteful number, since it uses less digits than its factorization.

13044012320021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1088736822.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13044012320021 its reverse (12002321044031), we get a palindrome (25046333364052).

The spelling of 13044012320021 in words is "thirteen trillion, forty-four billion, twelve million, three hundred twenty thousand, twenty-one".