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13026832450837 is a prime number
BaseRepresentation
bin1011110110010000101110…
…1110001000010100010101
31201010100112100111021001221
42331210023232020110111
53201412423101411322
643412235541050341
72513105023564132
oct275441356102425
951110470437057
1013026832450837
1141727153451a7
12156482b9b69b1
1373656aa3436a
143307058d1589
15178cd01729c7
hexbd90bb88515

13026832450837 has 2 divisors, whose sum is σ = 13026832450838. Its totient is φ = 13026832450836.

The previous prime is 13026832450769. The next prime is 13026832450897. The reversal of 13026832450837 is 73805423862031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12928634200881 + 98198249956 = 3595641^2 + 313366^2 .

It is an emirp because it is prime and its reverse (73805423862031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13026832450837 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13026832450897) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6513416225418 + 6513416225419.

It is an arithmetic number, because the mean of its divisors is an integer number (6513416225419).

Almost surely, 213026832450837 is an apocalyptic number.

It is an amenable number.

13026832450837 is a deficient number, since it is larger than the sum of its proper divisors (1).

13026832450837 is an equidigital number, since it uses as much as digits as its factorization.

13026832450837 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5806080, while the sum is 52.

The spelling of 13026832450837 in words is "thirteen trillion, twenty-six billion, eight hundred thirty-two million, four hundred fifty thousand, eight hundred thirty-seven".