Search a number
-
+
1304402143255 = 5260880428651
BaseRepresentation
bin10010111110110100011…
…011010010100000010111
311121200220000202111111221
4102332310123102200113
5132332403422041010
62435122320511211
7163145205164311
oct22766433224027
94550800674457
101304402143255
11463215005612
1219097577b507
139600a12ab33
14471c20a07b1
1523de5633dda
hex12fb46d2817

1304402143255 has 4 divisors (see below), whose sum is σ = 1565282571912. Its totient is φ = 1043521714600.

The previous prime is 1304402143237. The next prime is 1304402143313. The reversal of 1304402143255 is 5523412044031.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-1304402143255 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1304402143255.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130440214321 + ... + 130440214330.

It is an arithmetic number, because the mean of its divisors is an integer number (391320642978).

Almost surely, 21304402143255 is an apocalyptic number.

1304402143255 is a deficient number, since it is larger than the sum of its proper divisors (260880428657).

1304402143255 is an equidigital number, since it uses as much as digits as its factorization.

1304402143255 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 260880428656.

The product of its (nonzero) digits is 57600, while the sum is 34.

Adding to 1304402143255 its reverse (5523412044031), we get a palindrome (6827814187286).

The spelling of 1304402143255 in words is "one trillion, three hundred four billion, four hundred two million, one hundred forty-three thousand, two hundred fifty-five".

Divisors: 1 5 260880428651 1304402143255