Base | Representation |
---|---|
bin | 10010111110110100011… |
… | …011010010100000010111 |
3 | 11121200220000202111111221 |
4 | 102332310123102200113 |
5 | 132332403422041010 |
6 | 2435122320511211 |
7 | 163145205164311 |
oct | 22766433224027 |
9 | 4550800674457 |
10 | 1304402143255 |
11 | 463215005612 |
12 | 19097577b507 |
13 | 9600a12ab33 |
14 | 471c20a07b1 |
15 | 23de5633dda |
hex | 12fb46d2817 |
1304402143255 has 4 divisors (see below), whose sum is σ = 1565282571912. Its totient is φ = 1043521714600.
The previous prime is 1304402143237. The next prime is 1304402143313. The reversal of 1304402143255 is 5523412044031.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-1304402143255 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1304402143255.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130440214321 + ... + 130440214330.
It is an arithmetic number, because the mean of its divisors is an integer number (391320642978).
Almost surely, 21304402143255 is an apocalyptic number.
1304402143255 is a deficient number, since it is larger than the sum of its proper divisors (260880428657).
1304402143255 is an equidigital number, since it uses as much as digits as its factorization.
1304402143255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 260880428656.
The product of its (nonzero) digits is 57600, while the sum is 34.
Adding to 1304402143255 its reverse (5523412044031), we get a palindrome (6827814187286).
The spelling of 1304402143255 in words is "one trillion, three hundred four billion, four hundred two million, one hundred forty-three thousand, two hundred fifty-five".
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