1304402149999 has 4 divisors (see below), whose sum is σ = 1404740776936. Its totient is φ = 1204063523064.

The previous prime is 1304402149997. The next prime is 1304402150071. The reversal of 1304402149999 is 9999412044031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1304402149999 - 2¹ = 1304402149997 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1304402149997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50169313449 + ... + 50169313474.

It is an arithmetic number, because the mean of its divisors is an integer number (351185194234).

Almost surely, 2^{1304402149999} is an apocalyptic number.

1304402149999 is a deficient number, since it is larger than the sum of its proper divisors (100338626937).

1304402149999 is a wasteful number, since it uses less digits than its factorization.

1304402149999 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100338626936.

The product of its (nonzero) digits is 2519424, while the sum is 55.

The spelling of 1304402149999 in words is "one trillion, three hundred four billion, four hundred two million, one hundred forty-nine thousand, nine hundred ninety-nine".