Search a number
-
+
130440215051 is a prime number
BaseRepresentation
bin111100101111011010…
…1111011101000001011
3110110200121021111010222
41321132311323220023
54114120143340201
6135531242300255
712265300351106
oct1713665735013
9413617244128
10130440215051
1150357112223
12213441b768b
13c3ba156803
146455b3b73d
1535d681c91b
hex1e5ed7ba0b

130440215051 has 2 divisors, whose sum is σ = 130440215052. Its totient is φ = 130440215050.

The previous prime is 130440214997. The next prime is 130440215057. The reversal of 130440215051 is 150512044031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130440215051 - 214 = 130440198667 is a prime.

It is a super-2 number, since 2×1304402150512 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 130440215051.

It is not a weakly prime, because it can be changed into another prime (130440215057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220107525 + 65220107526.

It is an arithmetic number, because the mean of its divisors is an integer number (65220107526).

Almost surely, 2130440215051 is an apocalyptic number.

130440215051 is a deficient number, since it is larger than the sum of its proper divisors (1).

130440215051 is an equidigital number, since it uses as much as digits as its factorization.

130440215051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2400, while the sum is 26.

Adding to 130440215051 its reverse (150512044031), we get a palindrome (280952259082).

The spelling of 130440215051 in words is "one hundred thirty billion, four hundred forty million, two hundred fifteen thousand, fifty-one".