Base | Representation |
---|---|
bin | 10010111110110100011… |
… | …011100000101101001011 |
3 | 11121200220000212110022011 |
4 | 102332310123200231023 |
5 | 132332403430421134 |
6 | 2435122322040351 |
7 | 163145205526012 |
oct | 22766433405513 |
9 | 4550800773264 |
10 | 1304402201419 |
11 | 463215045289 |
12 | 1909757a90b7 |
13 | 9600a14b455 |
14 | 471c20b7a79 |
15 | 23de5646264 |
hex | 12fb46e0b4b |
1304402201419 has 2 divisors, whose sum is σ = 1304402201420. Its totient is φ = 1304402201418.
The previous prime is 1304402201383. The next prime is 1304402201513. The reversal of 1304402201419 is 9141022044031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1304402201419 - 217 = 1304402070347 is a prime.
It is a super-2 number, since 2×13044022014192 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1304402201719) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652201100709 + 652201100710.
It is an arithmetic number, because the mean of its divisors is an integer number (652201100710).
Almost surely, 21304402201419 is an apocalyptic number.
1304402201419 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304402201419 is an equidigital number, since it uses as much as digits as its factorization.
1304402201419 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
The spelling of 1304402201419 in words is "one trillion, three hundred four billion, four hundred two million, two hundred one thousand, four hundred nineteen".
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