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130440240214334 = 265220120107167
BaseRepresentation
bin11101101010001001111100…
…001011101011000100111110
3122002211222001121122100101022
4131222021330023223010332
5114044113102443324314
61141231230305344142
736321665515610561
oct3552117413530476
9562758047570338
10130440240214334
1138620439038206
1212768238638052
1357a260097032b
14242d4ac7bc4d8
1510130b3ac878e
hex76a27c2eb13e

130440240214334 has 4 divisors (see below), whose sum is σ = 195660360321504. Its totient is φ = 65220120107166.

The previous prime is 130440240214309. The next prime is 130440240214351. The reversal of 130440240214334 is 433412042044031.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 130440240214294 and 130440240214303.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32610060053582 + ... + 32610060053585.

It is an arithmetic number, because the mean of its divisors is an integer number (48915090080376).

Almost surely, 2130440240214334 is an apocalyptic number.

130440240214334 is a deficient number, since it is larger than the sum of its proper divisors (65220120107170).

130440240214334 is an equidigital number, since it uses as much as digits as its factorization.

130440240214334 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65220120107169.

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 130440240214334 its reverse (433412042044031), we get a palindrome (563852282258365).

The spelling of 130440240214334 in words is "one hundred thirty trillion, four hundred forty billion, two hundred forty million, two hundred fourteen thousand, three hundred thirty-four".

Divisors: 1 2 65220120107167 130440240214334