Base | Representation |
---|---|
bin | 10010111110110100011… |
… | …100101111110000010001 |
3 | 11121200220001110220110002 |
4 | 102332310130233300101 |
5 | 132332404021301301 |
6 | 2435122333015345 |
7 | 163145211344666 |
oct | 22766434576021 |
9 | 4550801426402 |
10 | 1304402525201 |
11 | 463215246576 |
12 | 190975924555 |
13 | 9600a232939 |
14 | 471c215da6d |
15 | 23de56ac16b |
hex | 12fb472fc11 |
1304402525201 has 2 divisors, whose sum is σ = 1304402525202. Its totient is φ = 1304402525200.
The previous prime is 1304402525131. The next prime is 1304402525297. The reversal of 1304402525201 is 1025252044031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1278145563601 + 26256961600 = 1130551^2 + 162040^2 .
It is a cyclic number.
It is not a de Polignac number, because 1304402525201 - 230 = 1303328783377 is a prime.
It is not a weakly prime, because it can be changed into another prime (1304402515201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652201262600 + 652201262601.
It is an arithmetic number, because the mean of its divisors is an integer number (652201262601).
Almost surely, 21304402525201 is an apocalyptic number.
It is an amenable number.
1304402525201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304402525201 is an equidigital number, since it uses as much as digits as its factorization.
1304402525201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 29.
Adding to 1304402525201 its reverse (1025252044031), we get a palindrome (2329654569232).
The spelling of 1304402525201 in words is "one trillion, three hundred four billion, four hundred two million, five hundred twenty-five thousand, two hundred one".
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