Base | Representation |
---|---|
bin | 11101101010001001111111… |
… | …111000001011010001101001 |
3 | 122002211222012221022011110121 |
4 | 131222021333320023101221 |
5 | 114044113214331242301 |
6 | 1141231240402243241 |
7 | 36322000200565432 |
oct | 3552117770132151 |
9 | 562758187264417 |
10 | 130440302212201 |
11 | 38620470033113 |
12 | 12768255356521 |
13 | 57a2610769767 |
14 | 242d4b6b1a489 |
15 | 10130b92733a1 |
hex | 76a27fe0b469 |
130440302212201 has 8 divisors (see below), whose sum is σ = 139007611609344. Its totient is φ = 122114325474240.
The previous prime is 130440302212163. The next prime is 130440302212223. The reversal of 130440302212201 is 102212203044031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 130440302212201 - 217 = 130440302081129 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130440302212601) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60333163680 + ... + 60333165841.
It is an arithmetic number, because the mean of its divisors is an integer number (17375951451168).
Almost surely, 2130440302212201 is an apocalyptic number.
It is an amenable number.
130440302212201 is a deficient number, since it is larger than the sum of its proper divisors (8567309397143).
130440302212201 is a wasteful number, since it uses less digits than its factorization.
130440302212201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 120666329591.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 130440302212201 its reverse (102212203044031), we get a palindrome (232652505256232).
The spelling of 130440302212201 in words is "one hundred thirty trillion, four hundred forty billion, three hundred two million, two hundred twelve thousand, two hundred one".
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