Base | Representation |
---|---|
bin | 11101101010001010000001… |
… | …100111001000111000110011 |
3 | 122002211222021222000222222102 |
4 | 131222022001213020320303 |
5 | 114044113244303103103 |
6 | 1141231243321531015 |
7 | 36322001003045615 |
oct | 3552120147107063 |
9 | 562758258028872 |
10 | 130440331300403 |
11 | 386204854a0553 |
12 | 12768263043a6b |
13 | 57a26167b2707 |
14 | 242d4ba92cdb5 |
15 | 10130bbabbe88 |
hex | 76a2819c8e33 |
130440331300403 has 2 divisors, whose sum is σ = 130440331300404. Its totient is φ = 130440331300402.
The previous prime is 130440331300361. The next prime is 130440331300519. The reversal of 130440331300403 is 304003133044031.
It is a weak prime.
It is an emirp because it is prime and its reverse (304003133044031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130440331300403 - 220 = 130440330251827 is a prime.
It is not a weakly prime, because it can be changed into another prime (130440331000403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220165650201 + 65220165650202.
It is an arithmetic number, because the mean of its divisors is an integer number (65220165650202).
Almost surely, 2130440331300403 is an apocalyptic number.
130440331300403 is a deficient number, since it is larger than the sum of its proper divisors (1).
130440331300403 is an equidigital number, since it uses as much as digits as its factorization.
130440331300403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 130440331300403 its reverse (304003133044031), we get a palindrome (434443464344434).
The spelling of 130440331300403 in words is "one hundred thirty trillion, four hundred forty billion, three hundred thirty-one million, three hundred thousand, four hundred three".
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