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13044041131313 is a prime number
BaseRepresentation
bin1011110111010000110101…
…1100000010010100110001
31201011222221122122210210002
42331310031130002110301
53202203144012200223
643424203314515345
72514254333135213
oct275641534022461
951158848583702
1013044041131313
114179a46185585
121568032b95b55
13738081030b2a
143314991b25b3
1517948ad1ae28
hexbdd0d702531

13044041131313 has 2 divisors, whose sum is σ = 13044041131314. Its totient is φ = 13044041131312.

The previous prime is 13044041131241. The next prime is 13044041131349. The reversal of 13044041131313 is 31313114044031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12257960292769 + 786080838544 = 3501137^2 + 886612^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13044041131313 is a prime.

It is not a weakly prime, because it can be changed into another prime (13044041131013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522020565656 + 6522020565657.

It is an arithmetic number, because the mean of its divisors is an integer number (6522020565657).

Almost surely, 213044041131313 is an apocalyptic number.

It is an amenable number.

13044041131313 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044041131313 is an equidigital number, since it uses as much as digits as its factorization.

13044041131313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 13044041131313 its reverse (31313114044031), we get a palindrome (44357155175344).

The spelling of 13044041131313 in words is "thirteen trillion, forty-four billion, forty-one million, one hundred thirty-one thousand, three hundred thirteen".