Base | Representation |
---|---|
bin | 1011110111010000110101… |
… | …1100010101110110100111 |
3 | 1201011222221122210212111200 |
4 | 2331310031130111312213 |
5 | 3202203144022230203 |
6 | 43424203320333543 |
7 | 2514254333620344 |
oct | 275641534256647 |
9 | 51158848725450 |
10 | 13044041211303 |
11 | 4179a4622a693 |
12 | 15680330142b3 |
13 | 73808105b36b |
14 | 3314991d37cb |
15 | 17948ad349a3 |
hex | bdd0d715da7 |
13044041211303 has 24 divisors (see below), whose sum is σ = 18987876414000. Its totient is φ = 8628542951424.
The previous prime is 13044041211301. The next prime is 13044041211361. The reversal of 13044041211303 is 30311214044031.
13044041211303 is a `hidden beast` number, since 1 + 3 + 0 + 4 + 404 + 121 + 130 + 3 = 666.
It is not a de Polignac number, because 13044041211303 - 21 = 13044041211301 is a prime.
It is a super-2 number, since 2×130440412113032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13044041211301) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3865818 + ... + 6405671.
It is an arithmetic number, because the mean of its divisors is an integer number (791161517250).
Almost surely, 213044041211303 is an apocalyptic number.
13044041211303 is a deficient number, since it is larger than the sum of its proper divisors (5943835202697).
13044041211303 is a wasteful number, since it uses less digits than its factorization.
13044041211303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10272591 (or 10272588 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 13044041211303 its reverse (30311214044031), we get a palindrome (43355255255334).
The spelling of 13044041211303 in words is "thirteen trillion, forty-four billion, forty-one million, two hundred eleven thousand, three hundred three".
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