130440424442 has 4 divisors (see below), whose sum is σ = 195660636666. Its totient is φ = 65220212220.

The previous prime is 130440424441. The next prime is 130440424463. The reversal of 130440424442 is 244424044031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 244424044031 = 17 ⋅14377884943.

It can be written as a sum of positive squares in only one way, i.e., 125761727641 + 4678696801 = 354629^2 + 68401^2 .

It is a super-2 number, since 2×130440424442² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130440424399 and 130440424408.

It is not an unprimeable number, because it can be changed into a prime (130440424441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32610106109 + ... + 32610106112.

Almost surely, 2^130440424442 is an apocalyptic number.

130440424442 is a deficient number, since it is larger than the sum of its proper divisors (65220212224).

130440424442 is an equidigital number, since it uses as much as digits as its factorization.

130440424442 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65220212223.

The product of its (nonzero) digits is 49152, while the sum is 32.

Adding to 130440424442 its reverse (244424044031), we get a palindrome (374864468473).

The spelling of 130440424442 in words is "one hundred thirty billion, four hundred forty million, four hundred twenty-four thousand, four hundred forty-two".