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130440525403 is a prime number
BaseRepresentation
bin111100101111011011…
…1000111011001011011
3110110200121212020212111
41321132313013121123
54114120233303103
6135531253053151
712265303112656
oct1713667073133
9413617766774
10130440525403
1150357304411
12213443271b7
13c3ba234b56
146455bbc89d
1535d687e86d
hex1e5edc765b

130440525403 has 2 divisors, whose sum is σ = 130440525404. Its totient is φ = 130440525402.

The previous prime is 130440525353. The next prime is 130440525433. The reversal of 130440525403 is 304525044031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130440525403 - 213 = 130440517211 is a prime.

It is not a weakly prime, because it can be changed into another prime (130440525433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220262701 + 65220262702.

It is an arithmetic number, because the mean of its divisors is an integer number (65220262702).

Almost surely, 2130440525403 is an apocalyptic number.

130440525403 is a deficient number, since it is larger than the sum of its proper divisors (1).

130440525403 is an equidigital number, since it uses as much as digits as its factorization.

130440525403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 130440525403 its reverse (304525044031), we get a palindrome (434965569434).

The spelling of 130440525403 in words is "one hundred thirty billion, four hundred forty million, five hundred twenty-five thousand, four hundred three".