Base | Representation |
---|---|
bin | 111100101111011011… |
… | …1000111011001011011 |
3 | 110110200121212020212111 |
4 | 1321132313013121123 |
5 | 4114120233303103 |
6 | 135531253053151 |
7 | 12265303112656 |
oct | 1713667073133 |
9 | 413617766774 |
10 | 130440525403 |
11 | 50357304411 |
12 | 213443271b7 |
13 | c3ba234b56 |
14 | 6455bbc89d |
15 | 35d687e86d |
hex | 1e5edc765b |
130440525403 has 2 divisors, whose sum is σ = 130440525404. Its totient is φ = 130440525402.
The previous prime is 130440525353. The next prime is 130440525433. The reversal of 130440525403 is 304525044031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130440525403 - 213 = 130440517211 is a prime.
It is not a weakly prime, because it can be changed into another prime (130440525433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220262701 + 65220262702.
It is an arithmetic number, because the mean of its divisors is an integer number (65220262702).
Almost surely, 2130440525403 is an apocalyptic number.
130440525403 is a deficient number, since it is larger than the sum of its proper divisors (1).
130440525403 is an equidigital number, since it uses as much as digits as its factorization.
130440525403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 130440525403 its reverse (304525044031), we get a palindrome (434965569434).
The spelling of 130440525403 in words is "one hundred thirty billion, four hundred forty million, five hundred twenty-five thousand, four hundred three".
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