130441020141103 has 4 divisors (see below), whose sum is σ = 149075451589840. Its totient is φ = 111806588692368.

The previous prime is 130441020141071. The next prime is 130441020141109. The reversal of 130441020141103 is 301141020144031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130441020141103 - 2⁵ = 130441020141071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130441020141109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9317215724358 + ... + 9317215724371.

It is an arithmetic number, because the mean of its divisors is an integer number (37268862897460).

Almost surely, 2^{130441020141103} is an apocalyptic number.

130441020141103 is a deficient number, since it is larger than the sum of its proper divisors (18634431448737).

130441020141103 is an equidigital number, since it uses as much as digits as its factorization.

130441020141103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18634431448736.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 130441020141103 its reverse (301141020144031), we get a palindrome (431582040285134).

The spelling of 130441020141103 in words is "one hundred thirty trillion, four hundred forty-one billion, twenty million, one hundred forty-one thousand, one hundred three".