Base | Representation |
---|---|
bin | 11101101010001010101100… |
… | …000011010010000101110001 |
3 | 122002212001010120211101220002 |
4 | 131222022230003102011301 |
5 | 114044121224042234301 |
6 | 1141231442114555345 |
7 | 36322024440114164 |
oct | 3552125403220561 |
9 | 562761116741802 |
10 | 130441043321201 |
11 | 38620810400298 |
12 | 12768421598b55 |
13 | 57a26cb1703b2 |
14 | 242d547315adb |
15 | 101310e36616b |
hex | 76a2ac0d2171 |
130441043321201 has 2 divisors, whose sum is σ = 130441043321202. Its totient is φ = 130441043321200.
The previous prime is 130441043321189. The next prime is 130441043321261. The reversal of 130441043321201 is 102123340144031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 121331656954225 + 9109386366976 = 11015065^2 + 3018176^2 .
It is a cyclic number.
It is not a de Polignac number, because 130441043321201 - 230 = 130439969579377 is a prime.
It is not a weakly prime, because it can be changed into another prime (130441043321261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220521660600 + 65220521660601.
It is an arithmetic number, because the mean of its divisors is an integer number (65220521660601).
Almost surely, 2130441043321201 is an apocalyptic number.
It is an amenable number.
130441043321201 is a deficient number, since it is larger than the sum of its proper divisors (1).
130441043321201 is an equidigital number, since it uses as much as digits as its factorization.
130441043321201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 130441043321201 its reverse (102123340144031), we get a palindrome (232564383465232).
The spelling of 130441043321201 in words is "one hundred thirty trillion, four hundred forty-one billion, forty-three million, three hundred twenty-one thousand, two hundred one".
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