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130441043321201 is a prime number
BaseRepresentation
bin11101101010001010101100…
…000011010010000101110001
3122002212001010120211101220002
4131222022230003102011301
5114044121224042234301
61141231442114555345
736322024440114164
oct3552125403220561
9562761116741802
10130441043321201
1138620810400298
1212768421598b55
1357a26cb1703b2
14242d547315adb
15101310e36616b
hex76a2ac0d2171

130441043321201 has 2 divisors, whose sum is σ = 130441043321202. Its totient is φ = 130441043321200.

The previous prime is 130441043321189. The next prime is 130441043321261. The reversal of 130441043321201 is 102123340144031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121331656954225 + 9109386366976 = 11015065^2 + 3018176^2 .

It is a cyclic number.

It is not a de Polignac number, because 130441043321201 - 230 = 130439969579377 is a prime.

It is not a weakly prime, because it can be changed into another prime (130441043321261) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220521660600 + 65220521660601.

It is an arithmetic number, because the mean of its divisors is an integer number (65220521660601).

Almost surely, 2130441043321201 is an apocalyptic number.

It is an amenable number.

130441043321201 is a deficient number, since it is larger than the sum of its proper divisors (1).

130441043321201 is an equidigital number, since it uses as much as digits as its factorization.

130441043321201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 130441043321201 its reverse (102123340144031), we get a palindrome (232564383465232).

The spelling of 130441043321201 in words is "one hundred thirty trillion, four hundred forty-one billion, forty-three million, three hundred twenty-one thousand, two hundred one".