1304412024042 has 64 divisors (see below), whose sum is σ = 2912812531200. Its totient is φ = 432689921280.

The previous prime is 1304412023989. The next prime is 1304412024067. The reversal of 1304412024042 is 2404202144031.

1304412024042 is a `hidden beast` number, since 1 + 3 + 0 + 4 + 412 + 0 + 240 + 4 + 2 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 1304412023997 and 1304412024015.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12489334 + ... + 12593342.

It is an arithmetic number, because the mean of its divisors is an integer number (45512695800).

Almost surely, 2^{1304412024042} is an apocalyptic number.

1304412024042 is an abundant number, since it is smaller than the sum of its proper divisors (1608400507158).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1304412024042 is a wasteful number, since it uses less digits than its factorization.

1304412024042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105148 (or 105142 counting only the distinct ones).

The product of its (nonzero) digits is 6144, while the sum is 27.

Adding to 1304412024042 its reverse (2404202144031), we get a palindrome (3708614168073).

The spelling of 1304412024042 in words is "one trillion, three hundred four billion, four hundred twelve million, twenty-four thousand, forty-two".