130441321430242 has 4 divisors (see below), whose sum is σ = 195661982145366. Its totient is φ = 65220660715120.

The previous prime is 130441321430239. The next prime is 130441321430243. The reversal of 130441321430242 is 242034123144031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 103814885503681 + 26626435926561 = 10188959^2 + 5160081^2 .

It is a junction number, because it is equal to n+sod(n) for n = 130441321430198 and 130441321430207.

It is not an unprimeable number, because it can be changed into a prime (130441321430243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32610330357559 + ... + 32610330357562.

Almost surely, 2^{130441321430242} is an apocalyptic number.

130441321430242 is a deficient number, since it is larger than the sum of its proper divisors (65220660715124).

130441321430242 is an equidigital number, since it uses as much as digits as its factorization.

130441321430242 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65220660715123.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 130441321430242 its reverse (242034123144031), we get a palindrome (372475444574273).

The spelling of 130441321430242 in words is "one hundred thirty trillion, four hundred forty-one billion, three hundred twenty-one million, four hundred thirty thousand, two hundred forty-two".