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13044140412100 = 225271918143912343
BaseRepresentation
bin1011110111010001001101…
…0110110000110011000100
31201012000012120110210102021
42331310103112300303010
53202203344421141400
643424221222452524
72514256650043450
oct275642326606304
951160176423367
1013044140412100
114179a97225716
121568060294144
13738098782165
143314a8457660
151794948cc71a
hexbdd135b0cc4

13044140412100 has 288 divisors, whose sum is σ = 34320981094400. Its totient is φ = 4203546969600.

The previous prime is 13044140412097. The next prime is 13044140412103. The reversal of 13044140412100 is 121404144031.

13044140412100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (13044140412097) and next prime (13044140412103).

It is a Harshad number since it is a multiple of its sum of digits (25).

It is not an unprimeable number, because it can be changed into a prime (13044140412103) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1056798529 + ... + 1056810871.

Almost surely, 213044140412100 is an apocalyptic number.

13044140412100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13044140412100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17160490547200).

13044140412100 is an abundant number, since it is smaller than the sum of its proper divisors (21276840682300).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13044140412100 is a wasteful number, since it uses less digits than its factorization.

13044140412100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13003 (or 12996 counting only the distinct ones).

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 13044140412100 its reverse (121404144031), we get a palindrome (13165544556131).

The spelling of 13044140412100 in words is "thirteen trillion, forty-four billion, one hundred forty million, four hundred twelve thousand, one hundred".