Base | Representation |
---|---|
bin | 10010111110110101001… |
… | …000101011010010000110 |
3 | 11121200220212010222110101 |
4 | 102332311020223102012 |
5 | 132332414443304342 |
6 | 2435123423514314 |
7 | 163145411260255 |
oct | 22766510532206 |
9 | 4550825128411 |
10 | 1304414041222 |
11 | 4632207a1746 |
12 | 19097975899a |
13 | 9600c735556 |
14 | 471c38ba79c |
15 | 23de66d43b7 |
hex | 12fb522b486 |
1304414041222 has 4 divisors (see below), whose sum is σ = 1956621061836. Its totient is φ = 652207020610.
The previous prime is 1304414041219. The next prime is 1304414041237. The reversal of 1304414041222 is 2221404144031.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 326103510304 + ... + 326103510307.
It is an arithmetic number, because the mean of its divisors is an integer number (489155265459).
Almost surely, 21304414041222 is an apocalyptic number.
1304414041222 is a deficient number, since it is larger than the sum of its proper divisors (652207020614).
1304414041222 is an equidigital number, since it uses as much as digits as its factorization.
1304414041222 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 652207020613.
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 1304414041222 its reverse (2221404144031), we get a palindrome (3525818185253).
The spelling of 1304414041222 in words is "one trillion, three hundred four billion, four hundred fourteen million, forty-one thousand, two hundred twenty-two".
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