13044141021341 has 4 divisors (see below), whose sum is σ = 13044691686300. Its totient is φ = 13043590356384.

The previous prime is 13044141021319. The next prime is 13044141021343. The reversal of 13044141021341 is 14312014144031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1461792230116 + 11582348791225 = 1209046^2 + 3403285^2 .

It is a cyclic number.

It is not a de Polignac number, because 13044141021341 - 2²² = 13044136827037 is a prime.

It is a super-2 number, since 2×13044141021341² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044141021343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 275296946 + ... + 275344323.

It is an arithmetic number, because the mean of its divisors is an integer number (3261172921575).

Almost surely, 2^{13044141021341} is an apocalyptic number.

It is an amenable number.

13044141021341 is a deficient number, since it is larger than the sum of its proper divisors (550664959).

13044141021341 is an equidigital number, since it uses as much as digits as its factorization.

13044141021341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 550664958.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 13044141021341 its reverse (14312014144031), we get a palindrome (27356155165372).

The spelling of 13044141021341 in words is "thirteen trillion, forty-four billion, one hundred forty-one million, twenty-one thousand, three hundred forty-one".