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1304414434201 is a prime number
BaseRepresentation
bin10010111110110101001…
…010001011001110011001
311121200220212212221112011
4102332311022023032121
5132332420043343301
62435123440145521
7163145414515054
oct22766512131631
94550825787464
101304414434201
11463220a3aa1a
121909799082a1
139600c842398
14471c397da9b
1523de6760a51
hex12fb528b399

1304414434201 has 2 divisors, whose sum is σ = 1304414434202. Its totient is φ = 1304414434200.

The previous prime is 1304414434133. The next prime is 1304414434207. The reversal of 1304414434201 is 1024344144031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1100508000601 + 203906433600 = 1049051^2 + 451560^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1304414434201 is a prime.

It is not a weakly prime, because it can be changed into another prime (1304414434207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652207217100 + 652207217101.

It is an arithmetic number, because the mean of its divisors is an integer number (652207217101).

Almost surely, 21304414434201 is an apocalyptic number.

It is an amenable number.

1304414434201 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304414434201 is an equidigital number, since it uses as much as digits as its factorization.

1304414434201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 1304414434201 its reverse (1024344144031), we get a palindrome (2328758578232).

The spelling of 1304414434201 in words is "one trillion, three hundred four billion, four hundred fourteen million, four hundred thirty-four thousand, two hundred one".