130442023321433 has 2 divisors, whose sum is σ = 130442023321434. Its totient is φ = 130442023321432.

The previous prime is 130442023321411. The next prime is 130442023321471. The reversal of 130442023321433 is 334123320244031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108319553198224 + 22122470123209 = 10407668^2 + 4703453^2 .

It is a cyclic number.

It is not a de Polignac number, because 130442023321433 - 2¹⁰ = 130442023320409 is a prime.

It is a super-2 number, since 2×130442023321433² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130442023321393 and 130442023321402.

It is not a weakly prime, because it can be changed into another prime (130442023321033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65221011660716 + 65221011660717.

It is an arithmetic number, because the mean of its divisors is an integer number (65221011660717).

Almost surely, 2^{130442023321433} is an apocalyptic number.

It is an amenable number.

130442023321433 is a deficient number, since it is larger than the sum of its proper divisors (1).

130442023321433 is an equidigital number, since it uses as much as digits as its factorization.

130442023321433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 124416, while the sum is 35.

Adding to 130442023321433 its reverse (334123320244031), we get a palindrome (464565343565464).

The spelling of 130442023321433 in words is "one hundred thirty trillion, four hundred forty-two billion, twenty-three million, three hundred twenty-one thousand, four hundred thirty-three".