Base | Representation |
---|---|
bin | 1011110111010001011100… |
… | …1010100001111001101111 |
3 | 1201012000101000201100122120 |
4 | 2331310113022201321233 |
5 | 3202204012301023343 |
6 | 43424231424244023 |
7 | 2514261354152145 |
oct | 275642712417157 |
9 | 51160330640576 |
10 | 13044204314223 |
11 | 417a01a301295 |
12 | 1568079770613 |
13 | 7380a8a97274 |
14 | 3314b2b2d595 |
15 | 17949a301683 |
hex | bdd172a1e6f |
13044204314223 has 4 divisors (see below), whose sum is σ = 17392272418968. Its totient is φ = 8696136209480.
The previous prime is 13044204314213. The next prime is 13044204314233. The reversal of 13044204314223 is 32241340244031.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (13044204314213) and next prime (13044204314233).
It is a cyclic number.
It is not a de Polignac number, because 13044204314223 - 25 = 13044204314191 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13044204314213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2174034052368 + ... + 2174034052373.
It is an arithmetic number, because the mean of its divisors is an integer number (4348068104742).
Almost surely, 213044204314223 is an apocalyptic number.
13044204314223 is a deficient number, since it is larger than the sum of its proper divisors (4348068104745).
13044204314223 is an equidigital number, since it uses as much as digits as its factorization.
13044204314223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4348068104744.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 13044204314223 its reverse (32241340244031), we get a palindrome (45285544558254).
The spelling of 13044204314223 in words is "thirteen trillion, forty-four billion, two hundred four million, three hundred fourteen thousand, two hundred twenty-three".
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