Base | Representation |
---|---|
bin | 1011110111010001011100… |
… | …1010100001111001111001 |
3 | 1201012000101000201100122221 |
4 | 2331310113022201321321 |
5 | 3202204012301023413 |
6 | 43424231424244041 |
7 | 2514261354152161 |
oct | 275642712417171 |
9 | 51160330640587 |
10 | 13044204314233 |
11 | 417a01a3012a4 |
12 | 1568079770621 |
13 | 7380a8a97281 |
14 | 3314b2b2d5a1 |
15 | 17949a30168d |
hex | bdd172a1e79 |
13044204314233 has 2 divisors, whose sum is σ = 13044204314234. Its totient is φ = 13044204314232.
The previous prime is 13044204314213. The next prime is 13044204314237. The reversal of 13044204314233 is 33241340244031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9219160198249 + 3825044115984 = 3036307^2 + 1955772^2 .
It is a cyclic number.
It is not a de Polignac number, because 13044204314233 - 225 = 13044170759801 is a prime.
It is not a weakly prime, because it can be changed into another prime (13044204314237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522102157116 + 6522102157117.
It is an arithmetic number, because the mean of its divisors is an integer number (6522102157117).
Almost surely, 213044204314233 is an apocalyptic number.
It is an amenable number.
13044204314233 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044204314233 is an equidigital number, since it uses as much as digits as its factorization.
13044204314233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 82944, while the sum is 34.
Adding to 13044204314233 its reverse (33241340244031), we get a palindrome (46285544558264).
The spelling of 13044204314233 in words is "thirteen trillion, forty-four billion, two hundred four million, three hundred fourteen thousand, two hundred thirty-three".
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