Base | Representation |
---|---|
bin | 1011110111010001100101… |
… | …1110001100000111011111 |
3 | 1201012000110201112221011011 |
4 | 2331310121132030013133 |
5 | 3202204102203203203 |
6 | 43424235330040051 |
7 | 2514262334156533 |
oct | 275643136140737 |
9 | 51160421487134 |
10 | 13044243022303 |
11 | 417a03a13a239 |
12 | 156808a719027 |
13 | 7380b3acaa5c |
14 | 3314b7d27bc3 |
15 | 17949d8ea76d |
hex | bdd1978c1df |
13044243022303 has 8 divisors (see below), whose sum is σ = 13735502290800. Its totient is φ = 12353455770048.
The previous prime is 13044243022301. The next prime is 13044243022319. The reversal of 13044243022303 is 30322034244031.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13044243022303 - 21 = 13044243022301 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13044243022301) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 117947326 + ... + 118057867.
It is an arithmetic number, because the mean of its divisors is an integer number (1716937786350).
Almost surely, 213044243022303 is an apocalyptic number.
13044243022303 is a deficient number, since it is larger than the sum of its proper divisors (691259268497).
13044243022303 is a wasteful number, since it uses less digits than its factorization.
13044243022303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 236008121.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 13044243022303 its reverse (30322034244031), we get a palindrome (43366277266334).
The spelling of 13044243022303 in words is "thirteen trillion, forty-four billion, two hundred forty-three million, twenty-two thousand, three hundred three".
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