130442533 has 4 divisors (see below), whose sum is σ = 140476588. Its totient is φ = 120408480.

The previous prime is 130442527. The next prime is 130442539. The reversal of 130442533 is 335244031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 335244031 = 29 ⋅11560139.

It is an interprime number because it is at equal distance from previous prime (130442527) and next prime (130442539).

It can be written as a sum of positive squares in 2 ways, for example, as 49028004 + 81414529 = 7002^2 + 9023^2 .

It is a cyclic number.

It is not a de Polignac number, because 130442533 - 2²¹ = 128345381 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130442498 and 130442507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130442539) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5017008 + ... + 5017033.

It is an arithmetic number, because the mean of its divisors is an integer number (35119147).

Almost surely, 2^130442533 is an apocalyptic number.

130442533 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

130442533 is a deficient number, since it is larger than the sum of its proper divisors (10034055).

130442533 is a wasteful number, since it uses less digits than its factorization.

130442533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10034054.

The product of its (nonzero) digits is 4320, while the sum is 25.

The square root of 130442533 is about 11421.1441195705. The cubic root of 130442533 is about 507.1538668849.

Adding to 130442533 its reverse (335244031), we get a palindrome (465686564).

The spelling of 130442533 in words is "one hundred thirty million, four hundred forty-two thousand, five hundred thirty-three".