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13044301000001 is a prime number
BaseRepresentation
bin1011110111010001110011…
…1011010110110101000001
31201012000121202122111121022
42331310130323112311001
53202204212024000001
643424245200435225
72514263640031655
oct275643473266501
951160552574538
1013044301000001
11417a069939797
1215680a6018b15
137380c2b1a39b
143314c18daa65
151794a3a4e11b
hexbdd1ced6d41

13044301000001 has 2 divisors, whose sum is σ = 13044301000002. Its totient is φ = 13044301000000.

The previous prime is 13044300999991. The next prime is 13044301000013. The reversal of 13044301000001 is 10000010344031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6951401175601 + 6092899824400 = 2636551^2 + 2468380^2 .

It is a cyclic number.

It is not a de Polignac number, because 13044301000001 - 218 = 13044300737857 is a prime.

It is not a weakly prime, because it can be changed into another prime (13044301080001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522150500000 + 6522150500001.

It is an arithmetic number, because the mean of its divisors is an integer number (6522150500001).

Almost surely, 213044301000001 is an apocalyptic number.

It is an amenable number.

13044301000001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044301000001 is an equidigital number, since it uses as much as digits as its factorization.

13044301000001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 13044301000001 its reverse (10000010344031), we get a palindrome (23044311344032).

The spelling of 13044301000001 in words is "thirteen trillion, forty-four billion, three hundred one million, one", and thus it is an aban number.