Base | Representation |
---|---|
bin | 1011110111010001110011… |
… | …1100111000011111010001 |
3 | 1201012000121210101211022201 |
4 | 2331310130330320133101 |
5 | 3202204212124300032 |
6 | 43424245213203201 |
7 | 2514263643316126 |
oct | 275643474703721 |
9 | 51160553354281 |
10 | 13044301400017 |
11 | 417a06a092288 |
12 | 15680a6190501 |
13 | 7380c2c2a494 |
14 | 3314c19a274d |
15 | 1794a3acc8e7 |
hex | bdd1cf387d1 |
13044301400017 has 2 divisors, whose sum is σ = 13044301400018. Its totient is φ = 13044301400016.
The previous prime is 13044301399951. The next prime is 13044301400077. The reversal of 13044301400017 is 71000410344031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9668424329281 + 3375877070736 = 3109409^2 + 1837356^2 .
It is a cyclic number.
It is not a de Polignac number, because 13044301400017 - 27 = 13044301399889 is a prime.
It is not a weakly prime, because it can be changed into another prime (13044301400077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522150700008 + 6522150700009.
It is an arithmetic number, because the mean of its divisors is an integer number (6522150700009).
Almost surely, 213044301400017 is an apocalyptic number.
It is an amenable number.
13044301400017 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044301400017 is an equidigital number, since it uses as much as digits as its factorization.
13044301400017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 13044301400017 its reverse (71000410344031), we get a palindrome (84044711744048).
The spelling of 13044301400017 in words is "thirteen trillion, forty-four billion, three hundred one million, four hundred thousand, seventeen".
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