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13044303424003 is a prime number
BaseRepresentation
bin1011110111010001110100…
…0100100110101000000011
31201012000121221012122201011
42331310131010212220003
53202204213134032003
643424245324421351
72514263666446015
oct275643504465003
951160557178634
1013044303424003
11417a0702449a5
1215680a69a7857
137380c34887c7
143314c1d6c1b5
151794a3d7c46d
hexbdd1d126a03

13044303424003 has 2 divisors, whose sum is σ = 13044303424004. Its totient is φ = 13044303424002.

The previous prime is 13044303423997. The next prime is 13044303424043. The reversal of 13044303424003 is 30042430344031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13044303424003 - 213 = 13044303415811 is a prime.

It is not a weakly prime, because it can be changed into another prime (13044303424043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522151712001 + 6522151712002.

It is an arithmetic number, because the mean of its divisors is an integer number (6522151712002).

Almost surely, 213044303424003 is an apocalyptic number.

13044303424003 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044303424003 is an equidigital number, since it uses as much as digits as its factorization.

13044303424003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 31.

Adding to 13044303424003 its reverse (30042430344031), we get a palindrome (43086733768034).

The spelling of 13044303424003 in words is "thirteen trillion, forty-four billion, three hundred three million, four hundred twenty-four thousand, three".