Base | Representation |
---|---|
bin | 1011110111010001110100… |
… | …0100100110101000000011 |
3 | 1201012000121221012122201011 |
4 | 2331310131010212220003 |
5 | 3202204213134032003 |
6 | 43424245324421351 |
7 | 2514263666446015 |
oct | 275643504465003 |
9 | 51160557178634 |
10 | 13044303424003 |
11 | 417a0702449a5 |
12 | 15680a69a7857 |
13 | 7380c34887c7 |
14 | 3314c1d6c1b5 |
15 | 1794a3d7c46d |
hex | bdd1d126a03 |
13044303424003 has 2 divisors, whose sum is σ = 13044303424004. Its totient is φ = 13044303424002.
The previous prime is 13044303423997. The next prime is 13044303424043. The reversal of 13044303424003 is 30042430344031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13044303424003 - 213 = 13044303415811 is a prime.
It is not a weakly prime, because it can be changed into another prime (13044303424043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522151712001 + 6522151712002.
It is an arithmetic number, because the mean of its divisors is an integer number (6522151712002).
Almost surely, 213044303424003 is an apocalyptic number.
13044303424003 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044303424003 is an equidigital number, since it uses as much as digits as its factorization.
13044303424003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 13044303424003 its reverse (30042430344031), we get a palindrome (43086733768034).
The spelling of 13044303424003 in words is "thirteen trillion, forty-four billion, three hundred three million, four hundred twenty-four thousand, three".
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