Base | Representation |
---|---|
bin | 1011110111010001110100… |
… | …0100101000110101010100 |
3 | 1201012000121221020010010000 |
4 | 2331310131010220311110 |
5 | 3202204213134324134 |
6 | 43424245324531300 |
7 | 2514263666514252 |
oct | 275643504506524 |
9 | 51160557203100 |
10 | 13044303433044 |
11 | 417a070250774 |
12 | 15680a69b0b30 |
13 | 7380c348c960 |
14 | 3314c1d715d2 |
15 | 1794a3d7ee99 |
hex | bdd1d128d54 |
13044303433044 has 240 divisors, whose sum is σ = 37253060925696. Its totient is φ = 3955791168000.
The previous prime is 13044303433037. The next prime is 13044303433079. The reversal of 13044303433044 is 44033430344031.
13044303433044 is a `hidden beast` number, since 1 + 3 + 0 + 4 + 4 + 3 + 0 + 343 + 304 + 4 = 666.
13044303433044 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×130443034330442 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (36).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 1285021369 + ... + 1285031519.
Almost surely, 213044303433044 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13044303433044, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18626530462848).
13044303433044 is an abundant number, since it is smaller than the sum of its proper divisors (24208757492652).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13044303433044 is a wasteful number, since it uses less digits than its factorization.
13044303433044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14548 (or 14537 counting only the distinct ones).
The product of its (nonzero) digits is 248832, while the sum is 36.
Adding to 13044303433044 its reverse (44033430344031), we get a palindrome (57077733777075).
The spelling of 13044303433044 in words is "thirteen trillion, forty-four billion, three hundred three million, four hundred thirty-three thousand, forty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •