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13044313447001 is a prime number
BaseRepresentation
bin1011110111010001110110…
…1010110101101001011001
31201012000122122001212200022
42331310131222311221121
53202204223220301001
643424250323320225
72514264150602414
oct275643552655131
951160578055608
1013044313447001
11417a075970371
1215680aa220075
137380c5587985
143314c341ab7b
151794a4bac11b
hexbdd1dab5a59

13044313447001 has 2 divisors, whose sum is σ = 13044313447002. Its totient is φ = 13044313447000.

The previous prime is 13044313446947. The next prime is 13044313447063. The reversal of 13044313447001 is 10074431344031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12603316513225 + 440996933776 = 3550115^2 + 664076^2 .

It is a cyclic number.

It is not a de Polignac number, because 13044313447001 - 26 = 13044313446937 is a prime.

It is a super-2 number, since 2×130443134470012 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13044313447301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522156723500 + 6522156723501.

It is an arithmetic number, because the mean of its divisors is an integer number (6522156723501).

Almost surely, 213044313447001 is an apocalyptic number.

It is an amenable number.

13044313447001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044313447001 is an equidigital number, since it uses as much as digits as its factorization.

13044313447001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48384, while the sum is 35.

The spelling of 13044313447001 in words is "thirteen trillion, forty-four billion, three hundred thirteen million, four hundred forty-seven thousand, one".